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Chapter 10
  • Chemical Quantities
  • or
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 How you measure how much?
  • You can measure mass,
  • or volume,
  • or you can count pieces.
  • We measure mass in grams.
  • We measure volume in liters.
  • We count pieces in MOLES.
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Moles
  • Defined as the number of carbon atoms in exactly 12 grams of carbon-12.
  • 1 mole is 6.02 x 1023  particles.
  • Treat it like a very large dozen
  • 6.02 x 1023  is called Avogadro's number.
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Representative particles
  • The smallest pieces of a substance.
  • For an element it is an atom.
    • Unless it is diatomic
  • For a molecular compound it is a molecule.
  • For an ionic compound it is a formula unit.
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Conversion factors
  • Used to change units.
  • Three questions
    • What unit do you want to get rid of?
    • Where does it go to cancel out?
    • What can you change it into?
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Calculation question
  • How many molecules of CO2 are the in 4.56 moles of CO2 ?
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Calculation question
  • How many moles of water is 5.87 x 1022  molecules?
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Calculation question
  • How many atoms of  carbon are there in 1.23 moles of C6H12O6 ?
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Measuring Moles
  • The amu was one twelfth the mass of a carbon 12 atom.
  • Since the mole is the number of atoms in 12 grams of carbon-12,
  • the decimal number on the periodic table is
    • The mass of the average atom in amu
    • the mass of 1 mole of those atoms in grams.
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Gram Atomic Mass
  • The mass of 1 mole of an element in grams.
  • 12.01 grams of carbon has the same number of atoms as 1.01 grams of hydrogen and 55.85 grams of iron.
  • We can write this as 12.01 g C = 1 mole
  • We can count things by weighing them.
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Examples
  • How much would 2.34 moles of carbon weigh?
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Examples
  • How many moles of magnesium in 4.61 g of Mg?
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Examples
  • How much would 3.45 x 1022 atoms of U weigh?
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What about compounds?
  • in 1 mole of H2O molecules there are two moles of H atoms and 1 mole of O atoms
  • To find the mass of one mole of a compound
    • determine the moles of the elements they have
    • Find out how much they would weigh
    • add them up
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What about compounds?
  • What is the mass of one mole of  CH4?
  • 1 mole of C = 12.01 g
  • 4 mole of H x 1.01 g = 4.04g
  • 1 mole CH4 = 12.01 + 4.04 = 16.05g
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Molar Mass
  • The mass of 1 mole
  • What is the molar mass of Fe2O3?
  • 2 moles of Fe x 55.85 g = 111.70 g
  • 3 moles of O x 16.00 g  = 48.00 g
  • The GFM = 111.70 g + 48.00 g = 159.70g
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Using Molar Mass
  • Finding moles of compounds
  • Counting pieces by weighing
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Molar Mass
  • The number of grams in 1 mole of atoms, formula units, or molecules.
  • We can make conversion factors from these.
  • To change grams of a compound to moles of a compound.
  • Or moles to grams
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For example
  • How many moles is 5.69 g of NaOH?
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For example
  • How many moles is 5.69 g of NaOH?
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Gases and the Mole
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Gases
  • Many of the chemicals we deal with are gases.
  • They are difficult to weigh, so we’ll measure volume
  • Need to know how many moles of gas we have.
  • Two things affect the volume of a gas
  • Temperature and pressure
  • Compare at the same temp. and pressure.
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Standard Temperature and Pressure
  • Avogadro's Hypothesis - at the same temperature and pressure equal volumes of gas have the same number of particles.
  • 0ºC and 1 atmosphere pressure
  • Abbreviated atm
  • 273 K and 101.3 kPa
  • kPa is kiloPascal
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At Standard Temperature and Pressure
  • abbreviated STP
  • At STP 1 mole of gas occupies 22.4 L
  • Called the molar volume
  • Used for conversion factors
  • Moles to Liter and L to mol



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Examples
  • What is the volume of 4.59 mole of CO2 gas at STP?
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Density of a gas
  •  D = m /V
  • for a gas the units will be  g / L
  • We can determine the density of any gas at STP if we know its formula.
  • To find the density we need the mass and the volume.
  • If you assume you have 1 mole than the mass is the molar mass (PT)
  • At STP the volume is 22.4 L.
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Examples
  • Find the density of CO2 at STP.
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Quizdom
  • Find the density of CH4 at STP.
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The other way
  • Given the density, we can find the molar mass of the gas.
  • Again, pretend you have a mole at STP, so V = 22.4 L.
  • m = D x V
  • m is the mass of 1 mole, since you have 22.4 L of the stuff.
  • What is the molar mass of a gas with a density of 1.964 g/L?
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All the things we can change
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Percent Composition
  • Like all percents
  •  Part    x 100 %   whole
  • Find the mass of each component,
  • divide by the total mass.
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Example
  • Calculate the percent composition of a compound that is 29.0 g of Ag with 4.30 g of S.
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Getting it from the formula
  • If we know the formula, assume you have 1 mole.
  • Then you know the pieces and the whole.
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Examples
  • Calculate the percent composition of C2H4?
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Examples
  • What is the percent composition of Aluminum carbonate.
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Percent to Mass
  • Multiply % by the total mass to find the mass of that component.
  • How much aluminum in 450 g of aluminum carbonate?
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Empirical Formula
  • From percentage to formula
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The Empirical Formula
  • The lowest whole number ratio of elements in a compound.
  • The molecular formula the actual ratio of elements in a compound.
  • The two can be the same.
  • CH2 empirical formula
  • C2H4 molecular formula
  • C3H6 molecular formula
  • H2O both
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Finding Empirical Formulas
  • Just find the lowest whole number ratio
  • C6H12O6
  • CH4N2
  • It is not just the ratio of atoms, it is also the ratio of moles of atoms.
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Calculating Empirical Formulas
  • Means we can get ratio from percent composition.
  • Assume you have a 100 g.
  • The percentages become grams.
  • Turn grams to moles.
  • Find lowest whole number ratio by dividing everything by the smallest moles.
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Example
  • Calculate the empirical formula of a compound composed of 38.67 % C, 16.22 % H, and 45.11 %N.
  • Assume 100 g so
  • 38.67 g C  x   1mol C     = 3.220 mole C 12.01 gC
  • 16.22 g H x   1mol H     = 16.1 mole H 1.01 gH
  • 45.11 g N  x   1mol N   = 3.220 mole N 14.01 gN
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Example
  • The ratio is 3.220 mol C  = 1 mol C        3.220 molN      1 mol N
  • The ratio is 16.1  mol H  =  5 mol H        3.220 molN      1 mol N
  • C1H5N1
  • Caffeine is 49.48% C, 5.15% H, 28.87% N and 16.49% O. What is its empirical formula?
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Empirical to molecular
  • Caffeine is 49.48% C, 5.15% H, 28.87% N and 16.49% O. What is its empirical formula?
  • Since the empirical formula is the lowest ratio the actual molecule would weigh the same or more.
  • By a whole number multiple.
  • Divide the actual molar mass by the the mass of one mole of the empirical formula.
  • You will get a whole number.
  • Multiply the empirical formula by this.
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Example
  • A compound has an empirical formula of ClCH2 and a molar mass of 98.96 g/mol. What is its molecular formula?
  • A compound has an empirical formula of CH2O and a molar mass of 180.0 g/mol. What is its molecular formula?


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Percent to molecular
  • Take the percent x the molar mass
    • This gives you mass in one mole of the compound
  • Change this to moles
    • You will get whole numbers
    • These are the subscripts
  • Caffeine is 49.48% C, 5.15% H, 28.87% N and 16.49% O. It has a molar mass of 194 g. What is its molecular formula?
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Example
  • Ibuprofen is 75.69 % C, 8.80 % H, 15.51 % O, and has a molar mass of about 207 g/mol. What is its molecular formula?